#1 : 18/01-22 07:31 MaxEnrik
Posts: 12
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name = 'AZ az 09!@#$%^&*()_+';
clean = /[^\pL\d]+/g; result = name.replace(clean, ''); return result Example: 'AZ az 09!@#$%^&*()_+' Expect: 'AZ az 09' But: 09 |
#2 : 18/01-22 10:03 David Lee
Posts: 1125
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This appears to be a limitation of the JavaScript regex implementation, since the regex [^\pL\d ] works perfectly in other replacement methods.
However \pL will match any Unicode letter from any language - not just Latin (English) script so it may not do exactly what you want anyway. Try the regex /[^a-z\d ]/gi or /[^A-Za-z\d ]/g |
#3 : 18/01-22 21:02 MaxEnrik
Posts: 12
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Reply to #2:
Thank you a lot! |